Question

discuss the natural roots for the given QE : 3 x²-4x-10= 0​

Answer 1

Answer:

$3x {}^{2} - 4x - 10 = 0 \\ a = 3 \\ b = - 4 \\ c = - 10 \\ d = b {}^{2} - 4ac \\ d = ( - 4) {}^{2} - 4 \times 3 \times - 10 \\ d = 16 + 120 \\ d = 136$

D>0+ve (Real and different roots)

Step-by-step explanation:

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Answer 2

Answer:

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Step by step explanation