Question

discuss the nature of roots -x²+3x+1​

Answer 1

eq. will have real and different roots

Answer 2

Answer:

-x^2+3x+1=0

-(x^2-3x-1)=0

x^2-3x-1=0=ax^2+bc+c=0

a=1,b=-3,c=-1

d=b^2-4ac

d=(-3)^2-4(1)(-1)

d=9+4

d=13

d>=0

real and distinct roots exist