Question

discuss the nature of roots x3-1/3x 1- 3/4 = 0​

Answer 1

Answer:

Step-by-step explanation:

x³-(1/3)x-(3/4)=0

Multiply both side by 12,

We get, 12x³-4x-9=0

Now let, f(x)=12x³-4x-9

f(-x)= -12x³+4x-9

Now by Decarte's Rule of sign, we can conclude that given equation has 3 real roots where one is a negative root and others two are positive