Question

discuss the nature of solution of the following Quadratic equation x²-8x+16=0​

Answer 1

The equation has real and equal roots.

Given: x²-8x+16=0​
To find: Nature of the equation
Solution:

Real roots:

We see that on any occasion we resolve a uninterrupted or a quadratic equating, we receive the profit changing of the equating or namely, we decipher of the equating. It is this 'solution' that we call palpable ancestries.

Hence, if an equating has authentic ancestries, the equating's resolutions or ancestries are part of the set of physical numbers. We contend that all the resolutions or ancestries of the equatings are not equal if the equating has apparent ancestries. When the discriminant of a quadratic equating is degree 0 , it has evident and obvious ancestries.

Lets take out the formula,
$ax^2 + bx + c = 0$
Discriminant = $D = b^2 - 4ac$

Equation= $x^2 - 8x +16 = 0$
Lets put out the discriminant $b^2 - 4ac = 0$
$(-8)^2 - 4 * 1 * 16 \\64-64\\=0$
So we get zero means roots are real and equal.

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