Question

discuss the nature of solution of the quardratic equation x²+2x+5=0​

Answer 1

Answer:

Step-by-step explanation:

Given that,

x² + 2x + 5 = 0

Comparing the given equation with ax² + bx + c = 0,

We have a = 1, b = 2 and c = 5

∴Discriminant = d = b² - 4ac = ( 2 )² - 4 ( 1 ) ( 5 ) = 4 - 20 = - 16.

There are no real roots. Roots are imaginary.