Question

Discuss the nature of solutions of the following quadratic equation x²+x-12=0

Answer 1

Step-by-step explanation:

gave any further questions

Answer 2

The roots are real and unequal.

Step-by-step explanation:

• To find the nature of the roots, we will determine the value of the determinant given by the formula

$D = b^2 - 4ac$

where a, b, and c are the coefficients of $x^2, x$ and constant in the quadratic equation.

• The given equation is $x^2 + x -12 = 0$

$a = 1, b = 1, c = -12$

$D = 1^2 - 4(1)(-12)$

$D = 1 + 48 = 49$

• Since, the value of D is greater than 0, hence, the given quadratic equation would have real and unequal roots.