discuss the nature of the root of 9 x² - 2 = 0
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Answer:
We have,
2x2−9x+9=0
Comparing that,
ax2+bx+c=0
Then,a=2,b=−9,c=9
We know that,
Nature of roots are
D=b2−4ac
=(−9)2−4×2×9
=81−72
=9>0
Roots are real.
Find them,
2x2−9x+9=0
2x2−(6+3)x+9=0
2x2−6x−3x+9=0
2x(x−3)−3(x−3)=0
(x−3)(2x−3)=0
If x−3=0 then, x=3
If 2x−3=0 then, x=23
Hence, x=3,23 is the answer.
Step-by-step explanation:
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Answered by
0
Answer:
Given that,
x
2
−x−2=0
Comparing with ax
2
+bx+c=0, we get,
a=1,b=−1 and c=−2
We know that, D=b
2
−4ac
∴ D=(−1)
2
−4(1)(−2)=1+8=9
⇒D>0
Since, the discriminant is positive, the given equation will have two distinct real roots.
Step-by-step explanation:
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