Question

discuss the nature of the roots for given quadratic equation 2x^-8x+8=0​

Answer 1

Step-by-step explanation:

2x^2-8x+8=0

Comparing with ax^2+bx+c

a=2,b= -8,c=8

b^2-4ac

(-8)^2-4(2)(8)

64-64

0

b^2-4ac=0

Roots are real and equal