Question

discuss the nature of the roots of the following equation : root 3x2 -2x-root 3 =0​

Answer 1

Answer:

sorry I don't .... .............

Answer 2

Step-by-step explanation:

$3 {x}^{2} - 2x - \sqrt{3} = 0$

b²-4ac=

${( - 2)}^{2} - 4 \times 3 \times ( - \sqrt{3} ) = \\ 4 + 12 \sqrt{3} > 0$

roots are real and unequal