Chemistry, asked by sovi1059, 1 year ago

Discuss the preparation of the phenol- formaldehyde resins.

Answers

Answered by Yuvrajpaul
1
Hope this helps you..

Phenol-formaldehyde resins, as a group, are formed by a step-growth polymerizationreaction that can be either acid- or base-catalysed. Since formaldehyde exists predominantly in solution as a dynamic equilibrium of methylene glycol oligomers, the concentration of the reactive form of formaldehyde depends on temperature and pH.

Phenol reacts with formaldehyde at the orthoand para sites (sites 2, 4 and 6) allowing up to 3 units of formaldehyde to attach to the ring. The initial reaction in all cases involves the formation of a hydroxymethyl phenol:

HOC6H5 + CH2O → HOC6H4CH2OH

The hydroxymethyl group is capable of reacting with either another free ortho or para site, or with another hydroxymethyl group. The first reaction gives a methylene bridge, and the second forms an ether bridge:

HOC6H4CH2OH + HOC6H5 → (HOC6H4)2CH2+ H2O2 HOC6H4CH2OH → (HOC6H4CH2)2O + H2O

The diphenol (HOC6H4)2CH2 (sometimes called a "dimer") is called bisphenol F, which is an important monomer in the production of epoxy resins. Bisphenol-F can further link generating tri- and tetra-and higher phenol oligomers.

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