Discuss the sum and different method to compare the EMF of the cell.
Answers
Answered by
3
Answer:
Describe the use of a potentiometer to compare the emf's of two cells by the sum difference method. Solution : ... The positive terminal of cell 1 of emf E1 is connected to the higher potential terminal A of the potentiometer, the negative terminal is connected to the galvanometer through the reversing key.
Similar questions