Question

Discuss the variation of weight of a body with the Latitude of Earth and Altitude of Earth.

Answer 1

The Earth is not a perfect sphere. It has a geoid shape, i.e., it's surface is not uniform. It's top and bottom is flattened and it's middle portion is widened. (Or, we can say that it has an "orange" like structure.)

Since, radius of Earth increases from poles to the equator, affecting gravitational force of attraction,

∴ The weight of the object decreases gradually, from poles to the equator.

Also, the more an object goes to higher altitudes, the less it weight becomes. This is because the value of "R" increases.

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Mathematical explanation:-

We know,

$\boxed{F = G \frac{m_1 m_2}{R^2}}$,

let, mass of an object on the surface of Earth be = m

Mass of Earth = M

Radius of Earth at poles = r

Radius at Equator = R

So that R > r

∴ In case of poles,

$F_1 = G \frac{Mm}{r^2}$

again, in case of force of attraction at equator,

$F_2 = G \frac{Mm}{R^2}$.

Since, R > r,

∴ $F_1 > F_2$

Or, gravitational force at poles > gravitational force at equator.

Answer 2

The Earth isn't an excellent sphere. It has a geoid shape, i.e., its floor isn't uniform. Its pinnacle and backside are flattened and its central component is widened.

Explanation:

• The weight of the frame varies with altitude. Weight decreases because the acceleration because of gravity decreases consequently weight decreases with growing altitude.
• The mass of an item stays steady with altitude.
• you weigh much less at the equator than on the North or South Pole, however, the distinction is small.
• Note that your frame itself does now no longer alternate. Rather it's far the pressure of gravity and different forces that alternate as you technique the poles.
• Since, the radius of Earth will increase from the poles to the equator, affecting the gravitational pressure of attraction,

∴ The weight of the item decreases gradually, from the poles to the equator.

• Also, the greater an item is going to better altitudes, the much less its weight becomes. This is due to the fee of "R" will increase.

gravitational pressure at poles > gravitational pressure on the equator.

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