Question

Disha is a cashier in a bank. She has currency notes of denominations Rs 100, Rs 50 and Rs 10, respectively. The ratio of the number of these notes is 2:3:5. The total cash with Disha is Rs 8,00,000. How many notes of each denomination does she have?



Answer in notebook only solution not explation! ​

Answer 1

Given :-

Disha is a cashier in a bank. She has currency notes of denominations Rs 100, Rs 50 and Rs 10, respectively. The ratio of the number of these notes is 2:3:5. The total cash with Disha is Rs 8,00,000.

To Find :-

How many notes of each denomination does she have?

Solution :-

Let the ratio be 2x,3x and 5x

Amount of Rs. 100 = 2x × 100 = 200x

Amount of Rs. 50 = 3x × 50 = 150x

Amount of Rs. 10 = 5x × 10 = 50x

Now

200x + 150x + 50 = 800000

400x = 800000

x = 800000/400

x = 8000/4

x = 2000

Rs. 100 note = 2x = 4000

Rs. 50 note = 3x = 6000

Rs. 10 note = 5x = 10000

Answer 2

Answer -

• Number of Rs 100 notes = 4000.
• Number of Rs 50 notes = 6000.
• Number of Rs 10 notes = 10000.

Given -

• Disha is a cashier in a bank.

• She has currency of notes of denominations of Rs 100, Rs 50 and Rs 10 respectively.

• The ratio of the number of these notes is 2 : 3 : 5.

To find -

• The number of notes of each denominations Disha has.

Step-by-step explanation -

As the ratio of the number of these notes is 2 : 3 : 5,

Let :-

• The number of Rs 100 notes be :- 2x × 100 = "200x".

• The number of Rs 50 notes be :- 3x × 50 = "150x".

• The number of Rs 10 notes be :- 5x × 10 = "50x".

Given that :-

• The total cash with Disha is Rs 8,00,000.

Therefore,

$\longrightarrow \sf200x + 150x + 50x = 800000$

$\longrightarrow \sf400x = 800000$

$\longrightarrow \sf x = \cancel{\dfrac{800000}{400}}$

$\longrightarrow \sf x = Rs \: 2000$

• The value of x is Rs 2000.

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Therefore,

Rs 100 notes :

$\hookrightarrow\bf2x = 2 \times 2000 = 4000.$

Rs 50 notes :

$\hookrightarrow \bf3x = 3 \times 2000 = 6000.$

Rs 10 notes :

$\hookrightarrow \bf5x = 5 \times 2000 = 10000.$

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