Question

Displacement (in metre) of a particle varies with time (in second) is given as y(t) = 4t^2 - 16t + 5.
Time taken by the particle to come to rest is ......​

Answer 1

Answer:

2 seconds

Explanation:

The displacement (s) is given as s=ut + 1/2at²

where u is the initial velocity and a is the acceleration.

Comparing with the given expression y(t) = 4t^2 - 16t + 5

ut = 16t, u = 16

1/2at² = 4t², a = 8m/s²

using v = u + at

0 = 16 - 8t

16/8 = t

∴ t = 2sec

hope it helps :)