displacement in metres of a particle moving along x-axis is given by X equal to 18 t + 5 t square calculate first the instantaneous velocity at equal to 4 second second every velocity between two equal to 4 second 10th equal to 5 second third instantaneous acceleration
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The displacement (in meter)...
PHYSICS
The displacement (in meter) of a particle moving along the x-axis is given x=18t+5t
2
. Calculate
(A) The instantaneous velocity at t = 2 sec
(B) Average velocity between t = 2 sec and t = 3 sec
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ANSWER
x=5t
2
+18t
(1)v=
dt
dx
=10t+18
att=2s,v=10×2+18=38m/s
(2)Average,velocity=
time
displacement
att=2,x=5(2)
2
+18×2=56m
t=3,x=5(3)
2
+18×3=99m
Averagevelocity=
3−2
99−56
=43 m/s
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