Question

Displacement Is Given By X=1+2T+3T² Calculate The Value Of Instantaneous Acceleration.

Answer 1

Answer:

use 2nd eq to solve it

Explanation:

Answer 2

The value of instantaneous acceleration is 6 units.

Explanation:

We have,

Displacement, $x=1+2t+3t^2$ ........(1)

Differentiate equation (1) wrt t we get :

$\dfrac{dx}{dt}=\dfrac{d(1+2t+3t^2)}{dt}\\\\\dfrac{dx}{dt}=0+2+6t$ ...........(2)

We know that, acceleration is $\dfrac{d^2x}{dt^2}=a$

Differentiate equation (2) wrt t again.

$\dfrac{d^2x}{dt^2}=\dfrac{d(0+2+6t)}{dt}\\\\\dfrac{d^2x}{dt^2}=a=6$

So, the value of instantaneous acceleration is 6 units.

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