Question

Displacement of a body is given by $x = 1 + 2t + 6t^{2}$. Find the value of instantaneous acceleration.

Answer 1

x = 1 + 2t + 6t²

$v$ = $\dfrac{dx}{dt}$

v = $\dfrac{1 + 2t + 6t^{2}}{dt}$

v = 2 + 12t

a = $\dfrac{dv}{dt}$

a = $\dfrac{2 + 12t}{dt}$

a = 12m/s²