Question

Displacement of a body us given by X=2+3t+4t squre where x is in meter and t is in second findout expression for velocity and accelaration​

Answer 1

Explanation:

$dispacement = x = 2 + 3t + 4 {t}^{2} \\ velocity = v = \frac{dx}{dt} \\ v = \frac{d(2 + 3t + 4 {t}^{2} )}{dt} = 0 + 3 + 8t = 3 + 8t \\ acceleration = a = \frac{dv}{dt} \\ a = \frac{d(3 + 8t)}{dt} = 0 + 8 = 8m{s}^{ - 2}$