Question

displacement of a particle at any instant is s =a-bt+ct^3, find initial velocity and initial acceleration​

Answer 1

Answer:

as differentiation

$n{x}^{n - 1}$

Answer 2

Answer:

initial velocity = -b ,

initial acceleration = 0.

Explanation:

Initially, time , t = 0.

And given that, displacement, $s =a-bt+ct^{3}$

It is known that, $v=\frac{ds}{dt} ;;;;;;;a =\frac{dv}{dt}$

So, $v =\frac{d}{dt}(a-bt+ct^{3})$

         $=0-b+3ct^{2}$

 And initial velocity = $-b+3(0)^{2}$

                                 =-b.

And acceleration, $a =\frac{d}{dt}(-b+3t^{2})$

                                 $=0+ 6t$

And initial acceleration = 6(0)

                                       = 0.