Question

Displacement of a particle depends on time as S=3t^3+6t^2-3t+4
a) velocity of particle at t=2sec
b) acceleration of particle at t=1sec

Answer 1

Answer:

S=3t^3+6t^2-3t+4

differentiating with respect to time t ,we get the velocity,

now,ds/dt=9t^2+12t-3

now , velocity at t=2sec is (9*2^2+12*2-3)=36+24-3=57 unit/sec

ds/dt=v=9t^2+12t-3________(1) [v=velocity]

differentiating with respect to time t the equation (1),we get the acceleration,

now,dv/dt=18t+12

now, acceleration of partical at t=1sec is

(18*1+12)=18+12=30 unit/sec^2

This is the required answer.