Question

Displacement of a particle in nth sec ,Sn: 4+2n where n is time in sec. Its displacement after 4seconds is?
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Answer 1

Answer:

The distance travelled is given by x=(t−2)

2

=t

2

–4t+4

As velocity is given by v=

dt

dx

v=2t−4

Distance covered=∫∣v∣dt

=∣t

2

–4t∣

=4t−t

2

for t=0to2

=t

2

−4tfor t=2to4

=8units

please brainliest mark