displacement of a particle is given by the expression x is equal to the 3t^2 + 70t - 9 where X is the metre and T is the second what is the acceleration
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x=3t^2+70t-9
dx/dt=d(3t^2+70t-90)/dt=6t+70
d(dx/dt)/dt=d(6t+70)/dt=6
Therefore, acceleration =6m/s^2
dx/dt=d(3t^2+70t-90)/dt=6t+70
d(dx/dt)/dt=d(6t+70)/dt=6
Therefore, acceleration =6m/s^2
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