Displacement of a particle of mass m moving in one dimension under action of force is related to time t=√x+3.displcement of particle when velocity is zero
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t = √x+3
It can be written as
√x = t-3
x =(t-3)² = t²+9-6t
we know,
v = dx/dt = d(t²+9-6t)/dt = 2t-6
Given, v = 0
so, 2t-6 = 0
2t = 6
t = 3seconds,
So, the velocity of particle at t=3 is zero. then, displacement at t=3 is
x = t²+9-6t = 9+9-18 = 0m
Cheers!
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