Question

Displacement of a particle starting from rest x( t)is given by x=[6t²-t³)m find the displacement , velocity , acceleration, at t =0 t = 2 seconds  t = 6.0 seconds  sketch the  graph of your result​

Answer 1

Explanation:

Displacement

a. at t = 0

Since the body is at rest displacement will be zero at t = 0 second.

b. at t = 2s

x = [6(2)^2 - (2)^3 ] = 16 m

c. at t = 6s

x = [6(6)^2 - (6)^3 ] = 0

Velocity

v = dx/dt = 12t - 3t^2 (see the pic)

Acceleration

a= dv/ dt = 12 - 6t ( see the pic)