Question

Displacement of moving particle is 1D under action of constant force F related to time is given by eqvation 4t= under root x+ 4 where x is m and t is second find velocity of particle at t= 2sec

Answer 1

Answer:

Heya!!!

Here's what you want :)

Explanation:

√x =t−3

⇒x=t2+9−6t

∴v=dx/dt

=2t−6  

(i) For the velocity to be zero , 2t−6=0⇒t=3sec.

The displacement is x=9+9−6×3=0

(ii) a=dv/ dt=2

∴At=0,v=−6ms−1

At t =6sec,v=6ms−1

∴ work done = change in K.E.=[K.Ef−K.E.i]

=1/2m(6)2−1/2m(6)2=0

Also, v at t= 2s,

=> 2t - 6 = 2(2) - 6 = 4 - 6 = -2 m/s

#Hope it helps :)

#Stay Safe :)

Answer 2

Hope it will help you to find the velocities of different objects in motion with the given equation of objects as followed above