Question

displacement of particle moving in y axis is y=2cost+5t-2 what is the acceleration at t=0s​

Answer 1

Answer:

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Answer 2

Answer:

Explanation:

$displacement\\y = 2cost + 5t -2$

velocity(v) = derivative of displacement w.r.t to time t

$\frac{dy}{dt} =\frac{d}{dt} (2cost + 5t -2)\\\\v= -2sint + 5$

acceleration(a) =  derivative of velocity w.r.t to time t

$\frac{dv}{dt } = \frac{d}{dt} (-2sint + 5)\\\\a = -2cost$

acceleration at t = 0 is

a = -2(cos0)

a = -2(1) = -2

∴ acceleration was 2 m/s² at  t=0s

(-ve) sign indicates the body is slowing down (deccelerating)