Question

displacement of x of a particle along the time by x = x is equal to Alpha minus Beta 2 +, white square find acceleration of the particle

Answer 1

hey friend here is your answer

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let's alpha = a1 and beta = a2

Now

we know , v = dx/dt

a = dv/dt

x = ao + a1t + a2t2

v= dx/dt = 0 + a1 + 2a2t

a=dv/dt = d/dt (a1+2a2t)
=0+2a2

differntiation of constant is 0...

so accleration of particle
= 2a2 = "2beta"

hope it will help you
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