displacement on particle s=3tsqaure-6t find velocity at t=1second
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The displacement of particle varies with time as S = 3t2 + 2t Find the velocity of the particle at t = 1 sec. (A) 5m/s (B) 2m/s (C) 8m/s (D) 6m/sRead more on Sarthaks.com - https://www.sarthaks.com/394479/the-displacement-of-particle-varies-with-time-as-3t-find-the-velocity-of-the-particle-at-se
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Answer:
s=t
3
−6t
2
+3t=4
v=
dt
ds
=3t
2
−12t+3
a=
dt
dv
=6t−12
So, acceleration will be zero at
6t−12=0
t=2sec
Then velocity at t = 3
v=3(2)
2
−12(2)+3
= 12-24+3
v=−9m/s
Step-by-step explanation:
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