Displacement(s) of a body in a time 't' is given by s=at^2+bt. Find dimension of a&b
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Dimension of a is L/T^2
Dimension of b is L/T
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The dimensions of a and b are [LT⁻³] and [LT⁻²] respectively.
Given,
The displacement of the body is given as s = at²+bt.
To Find,
The dimensions of a and b.
Solution,
The dimensional formula of displacement(s) is [LT⁻¹].
Now, the given expression is
s = at²+bt
So,
The dimensions of s will be the same as that of at² and bt.
[LT⁻¹] = a[T²]
a = [LT⁻³]
Now,
The dimensional formula of b will be
[LT⁻¹] = b[T¹]
b = [LT⁻²]
Hence, the dimensions of a and b are [LT⁻³] and [LT⁻²] respectively.
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