#
Displacement (s) of a particle is related to time (t)

as:

2 3 s at bt ct

, where a, b and c are

constants of the motion. The velocity of the

particle when its acceleration is zero is given by

## Answers

Answered by

41

__Given :-__

__Given :-__

__s = at + bt^2 - ct^3__

__accleration = 0__

**Solution:-**

**Solution:-**

__∴ v = dx/dt__

__ v = d(at + bt^2 - ct^3)/dt__

__ v = a + 2bt - 3ct ------------(1)__

__∴ ____accleration ____= d^2x/dt^2__

__ a = 0 + 2b _- bct__

__as , accl^n = 0 __

__so ,__

__ 2b - bct = 0 __

__t = d/3c__

__putting value of t in equation (1)__

__we get____ ,__

__ V = a + 2b * b/3c - 36 * b^2/ 9c^2__

__ V = a + 2b^2/3c - b^2/3c__

__ therfore :-__

__ V = a + b^2/3c__

__thank you__

Answered by

0

**Answer:**

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