Question

Displacement $x=5t^{2}+3t+6$. Find velocity and acceleration at time=2 sec.
Use $a=\frac{d^{2}x }{dt^{2} }$ and $v=\frac{dx}{dt}$.
Show the process also...

Answer 1

$\sf v = \frac{dx}{dt} = 10t + 3 + 0 = 10(2) + 3 = 20 + 3 = 23 \: sec$

$\sf \: a = \frac{ {d}^{2} x}{d {t}^{2} } = 10 + 0 = 10 \: sec$

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