Question

Displacement x of particle is x=4t^2-5t+25.find the position velocity and acceleration of particle at t=0

Answer 1

Answer: Position= 25m

Velocity= 5m/s

acceleration = 8m/s²

Explanation:

for position directly put t=0;

x=25m;

for velocity: as we know v=dx/dt;

x=4t²-5t+25

dx/dt= 8t-5, at t=0 dx/dt= -5 i.e v= 5m/s

for acceleration: a=d²x/dt²= 8m/s² (on differentiating dx/dt again w.r.t t)