Question

Displacement(y) of the particle is given by y=2t+t^2−2t^3The velocity of the particle when acceleration is zero is given by ?

Answer 1

Answer:

velocity at t = 1/6

Explanation:

velocity of the ;particle is the differential of the displacent of y.

.i.e. dy/dt = 2 + 2t – 6t^2

acceleration is the differentiation of velocity or double differentale of displacement.

.i.e. a = 2 – 12t = 0

t = 1/6

velocity at t = 1/6 now u can calcclate by putting t in velocity eqn.