Disproportionate reaction of perxenate ion
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Answered by
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This is the problem I am trying to balance for redox:
HXeO4⟶XeO64−+Xe+O2
It is supposed to be in a basic solution. However, my answer does not contain OH− on either side:
4HXeO4⟶XeO64−+3Xe+4O2+2H2O
I am wondering if I had made a mistake or if it's ok for the reaction to not contain OH− ions.
HXeO4⟶XeO64−+Xe+O2
It is supposed to be in a basic solution. However, my answer does not contain OH− on either side:
4HXeO4⟶XeO64−+3Xe+4O2+2H2O
I am wondering if I had made a mistake or if it's ok for the reaction to not contain OH− ions.
Answered by
23
Explanation:
disproportionation reaction is when a multiatomic species whose pertinent element has a specific oxidation state gets oxidized and reduced in two separate half-reactions, yielding two other products containing the same pertinent element. EXAMPLE: MANGANESE OXIDES. A convenient example is Mn2O3 becoming Mn2+ and MnO2.
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