Question

dissociation constant of HCN is 7.24×10^-10 Calculate the degree of dissociation and H3O+ in 0.01 M solution​

Answer 1

Explanation:

HCN⇌H+ +CN  

It is given that Ka =4×10−10 , [HCN]=0.2M and  [CN− ]=1M

According to law of mass action,

Ka = [HCN] [H+ ][CN− ]

From above equation we get [H+ ]=8×10  −11 M