Question

Dissociation relative to x. (y=20x-⁴+9). note= x^– 4​

Answer 1

Answer:

$y = 20 {x}^{ - 4} + 9$

$\frac{dy}{dx} = - 4 \times 20 {x}^{ - 3} + 0$

$\frac{dy}{dx} = - 80 {x}^{ - 3}$

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