Question

Dissociation relative to x. (y=sin(3x+5)​

Answer 1

Answer:

$Y = \sin(3x + 5)$

$\frac{dy}{dx} = \frac{d( \sin(3x + 5)) }{dx}$

$\frac{dy}{dx} = \cos(3x + 5) . \frac{d(3x + 5)}{dx}$

$\frac{dy}{dx} = \cos(3x + 5) .3 \times 1 + 0$

$\frac{dy}{dx} = \cos(3x + 5) .3$

$\frac{dy}{dx} = 3 \cos(3x + 5)$

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