Chemistry, asked by singhgurmeet9771, 10 months ago

dissolving 05g of silver wire in nitric acid and adding excess of hydrochloric acid to silver nitrate toge
oxide. In another experiment
Show that the above data illustrate the Law of Definite
2. Silver chloride is prepared by
silver chloride precipitated is separated, washed and dried. The weight of silver chloride is 0.66 g
(aheating 1 g ef silver metal in a current of dry chlorine gas till the metal is completely conveng
chloride. It is found to weigh 1.32 g
1
Mustrate the law of constant composition by the above data.​

Answers

Answered by shagunrajput012
2

Answer:

In the first experiment <br> Mass of silver = 0.5 g , Mass of silver chloride = 0.66 g <br> Percentage of silver

<br> Percentage of chlorine

<br> In the second experiment <br> Mass of silver = 1.0 g , Mass of silver chloride = 1.32 g <br> Percentage of silver

<br> percentage of chlorine

<br> The results are in accordance with the Law of Constant Composition.

Answered by manojkumarsingh297
0

Explanation:

dissolving 05g of silver wire in nitric acid and adding excess of hydrochloric acid to silver nitrate toge

oxide. In another experiment

Show that the above data illustrate the Law of Definite

2. Silver chloride is prepared by

silver chloride precipitated is separated, washed and dried. The weight of silver chloride is 0.66 g

(aheating 1 g ef silver metal in a current of dry chlorine gas till the metal is completely conveng

chloride. It is found to weigh 1.32 g

1

Mustrate the law of constant composition by the above data.

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