Dissolving 120 g of urea (mol. wt. 60) in 1000 g of water gave
a solution of density 1.15 g/mL. The molarity of the solution is
(a) 1.78 M (b) 2.00 M (c) 2.05 M (d) 2.22 M
Answers
answer : option (c) 2.05 M
given mass of Urea, w = 120g
and mass of water , W = 1000g
so, mass of solution = 1120 g
density of solution = 1.15 g/mL
then volume of solution = 1120/1.15 = 973.91 mL
number of mole of Urea = given mass/mol mass
= 120/60 = 2
now molarity = number of mole of solute/volume of solution in L
= 2/(973.91/1000)
= 2/(0.97391)
= 2.05 M
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Answer:
answer : option (c) 2.05 M
given mass of Urea, w = 120g
and mass of water , W = 1000g
so, mass of solution = 1120 g
density of solution = 1.15 g/mL
then volume of solution = 1120/1.15 = 973.91 mL
number of mole of Urea = given mass/mol mass
= 120/60 = 2
now molarity = number of mole of solute/volume of solution in L
= 2/(973.91/1000)
= 2/(0.97391)
= 2.05 M