Question

dissolving 120 gram of Urea Mol weight 60 in 8000 gram water of give solution of density 1.5 3 gram the molarity of solution is​

Answer 1

Answer: 2.05 M

Density of the solution 1.15gmL−1=MV1.15gmL−1=MV=1000+120V=1000+120V→V=11201.15→V=11201.15=973.91mL=973.91mL

⇒⇒ Molarity=WM=WM×1000VmL×1000VmL=120×1000×1.2560×973.91=120×1000×1.2560×973.91=2.05M