Distance = 2.44 billion light year
d = ( 2.44/3.2615) × 100 MPC
d = 74.8122 Mpc
Need explanation
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Answers
Generally, I am also confused with the mentioned numerical problem. But for a detailed explanation keep reading this answer :)
I am assuming that MPC = MEGAPARSEC
PROBABLE SOLUTION TO YOUR QUESTION :2.44 billion light years = 2440000000 light-years = 748.107 megaparsecs
Formula : For an approximate result, divide the length value by 3.262e+6 or use conversion methods in a correct way to reach the final result.
If MPC = MIlLIPARSEC, then 2440000000 light-years = 7.481 × 10^11 milliparsecs (Formula - for an approximate result, multiply the length value by 307)
Given :
Distance b/w two objects = 2.44 billion light year
To Find :
Distance b/w two objects in Mpc.
Explanation :
★ Remember :
- AU denotes Astronomical unit
- ly denotes Light year
- pc denotes parsec
1. Astronomical unit : mean displacement of earth from sun.
2. Light year : distance travelled by light in vacuum in 1yr.
3. Parsec : distance at which the mean radius of the earth's orbit subtends an angle of one second of arc.
★ Relation between astronomical unit, light year and parsec :
- 1 ly = 6.3 × 10⁴ Au
- 1 pc = 3.26 ly
Clearly,
Let's come to the question :)
★ Conversion : m ➝ pc