Question

distance =4800vmetres ,time =24seconds​

Answer 1

Correct Question :-

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$distance = 4800um \\ time = 24 \: s \\ find \: velocity.$

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Answer :-

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$distance \: = 4800 \times {10}^{ - 6} = 4.8 \times {10}^{ - 3}$

$\implies \: velocity = \frac{ 4.8 \times {10}^{ - 3} }{24} \\ = 2 \times {10}^{ - 4} m {s}^{ - 1}$

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HOPE THIS HELPS YOU!!!!!

Answer 2

distance=4800×10−6=4.8×10−3

distance=4800×10−6=4.8×10−3\begin{gathered} \implies \: velocity = \frac{ 4.8 \times {10}^{ - 3} }{24} \\ = 2 \times {10}^{ - 4} m {s}^{ - 1} \end{gathered}⟹velocity=244.8×10−3=2×10−4ms−1