Question

Distance between A(sin theta, cos theta), B(- sin theta, - cos THETA ) is
FULL EXPLANATION PLEASE ​

Answer 1

$\boxed {\blue{ \boxed{\sf Distance=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}}}}$

$\implies \sf Dist.=\sqrt{( \sin \theta + \sin \theta)^2+(\cos \theta + \cos \theta )^2}$

$\implies \sf Dist.=\sqrt{( 2\sin \theta)^2+(2\cos \theta)^2}$

$\implies \sf Dist.=\sqrt{4\sin^2 \theta+4\cos^2 \theta}$

$\implies \sf Dist.=\sqrt{4(\sin^2 \theta+\cos^2 \theta)}$

$\implies \sf Dist.=\sqrt{4(1)}$

$\implies \sf Dist.=\sqrt{4}$

$\orange{ \therefore \sf Dist.=2\:\:units}$

HOPE IT HELPS!!