Science, asked by Hithu6953, 11 months ago

Distance between Bholu’s and Golu’s house is 9 km. Bholu has to attend Golu’s birthday party at 7 O’ clock. He started his journey from his home at 6 O’ clock on his bicycle and covered a distance of 6 km in 40 min. At that point, he met Chintu and he spoke to him for 5 min and reached Golu’s birthday party at 7 O’ clock. With what speed, did he cover the second part of the journey? Calculate-his average speed for the entire journey. [NCERT Exemplar]

Answers

Answered by ishanit12345
20

Answer:answer is here

Explanation:the speed with which bholu covered the 2nd part of journey

=distance left to reach golu house/time left.

=9km-6km/1hour-45min

=12 km/h

average speed=total distance/total time

=9km/1hr

=9km/h

Answered by nandiniagarwal2102
5

Answer:

Explanation: The speed with which bholu covered the 2nd part of journey

= distance left / time left

= 9km - 6km / 1hour - 45 min

= 3km / 15 min

= 3000m / 15 x 60

= 3000/ 900

= 10/3 x 18/5

= 12 km/h

=> Average Speed = Total Distance / Total Time

=>  9 km / 1 hour

=> 9 km/h

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