Science, asked by Pandusmilie16281, 11 months ago

Distance between body centred atom and a corner atom in sodium (a = 4.225 A) is (a) 2.99 A (b) 2.54 A (c) 3.66 A (d) 3.17 A

Answers

Answered by mersalkeerthi46
0

Question 267 of 268

(1)

(2)

(3)

(4)


Answered by RamBala
1

Answer:

Explanation: distance between the centre atom and one of the corner atoms is equal to 2 r

BCC ,r=√3a/4

2r = 2*√3a/4=367.1pm

Option ( c ) ......

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