Distance between body centred atom and a corner atom in sodium (a = 4.225 A) is (a) 2.99 A (b) 2.54 A (c) 3.66 A (d) 3.17 A
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Question 267 of 268
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Explanation: distance between the centre atom and one of the corner atoms is equal to 2 r
BCC ,r=√3a/4
2r = 2*√3a/4=367.1pm
Option ( c ) ......
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