Question

Distance between consecutive compression and. rare faction of wave 30cm .if speed of sound is 360m/s find wave lengh frequency and time pwruodof wave

Answer 1

Wavelength (W) = 30 cm = 0.3 m
Wave velocity (V) = 360 m/s

V = f × W
=> f = V/W
=> f = 360/0.3
=> f = 1200 Hz.

Time period = 1/f = (1/1200) sec.

Answer 2

Given :

Distance between consecutive compression and rare faction of wave is 30 cm .

Speed of sound , v = 360 m/s .

To Find :

Wavelength frequency and time period of wave .

Solution :

We know , distance between consecutive compression and rare faction of wave is equal to the the wavelength .

Therefore , the wavelength is $\lambda=30\ cm = 0.3\ m$ .

Now , Frequency can be given by :

$\nu=\dfrac{c}{\lambda}\\\\\nu=\dfrac{360}{0.3}\\\\\nu=1200\ Hz$

Also , time period is the inverse of frequency .

$T=\dfrac{1}{\nu}\\\\T=\dfrac{1}{1200}\\T=8.33\times 10^{-4}\ s$

Hence , this is the required solution .

Learn More :

Waves

https://brainly.in/question/2215969