Question

Distance between Mark and Henry's house is 9 km. Mark has to attend Henry’s birthday party at 7 O’ clock. He started his journey from his home at 6 O’ clock on his bicycle and covered a distance of 6 km in 40 min. At that point, he met Alex and he spoke to him for 5 min and reached Henry’s birthday party at 7 O’ clock. With what speed, did he cover the second part of the journey? Calculate-his average speed for the entire journey. (plz give relevant question)

Answer 1

Answer:

3km=(v*15)/60

v=12km/h

Average speed=total distance/total time taken in the entire journey

Avg speed =9km/(40/60+15/60)h

Avg speed=9km/(0.66+0.25)h

Avg speed=9km/0.91h

Avg speed=9.9km/h

Answer 2

Answer:

Party start at 7’o clock

Total time spend by Bholu = 40 min (traveling) + 5 min (chatting) = 45 min

So Bholu has to reach Golu’s house within 15 min (1hour – 45 min)

The speed with which Bholu has to cover the second part of the journey is= 3/15 Km/min=12 Km/h

Average The average of Bholu’s in the entire journey is total distance divided by total the time taken is  

=Total distance traveled / total time taken  

=9Km/h