Question

Distance between Mark and Henry's house is 9 km. Mark has to attend Henry’s birthday party at 7 O’ clock. He started his journey from his home at 6 O’ clock on his bicycle and covered a distance of 6 km in 40 min. At that point, he met Alex and he spoke to him for 5 min and reached Henry’s birthday party at 7 O’ clock. With what speed, did he cover the second part of the journey? Calculate-his average speed for the entire journey.
(Please give step by step explanation.)

Answer 1

left house at 6 , distance due 9 km .

time 6:40 , distance due 3 km .

time 6:45 , distance due still 3 km . body at rest no movement .

time left 15 mins and distance covered 3 km .

therefore we can calculate this speed in the second part of the journey is 12 km / hr .

average speed is 9 km / hr

Answer 2

Answer:

Answer:

Explanation:

The speed with which Vijay covered the second part of journey

=  $\frac{Distance\:left\:to\:reach\:Ganesh's\:HOUSE}{time\:left}$

= $\frac{9km\:-\:6km}{1\:hour-\:45\:min}$

=  $\frac{3km}{\frac{1}{4\:}hour}$

$12kmph$

Average speed = $\frac{Total\:distance\:covered​}{Total\:time\:taken}\:=\:\frac{9km}{1hour}$

= 9kmph

6.6666666666667 min/km

=  6 min/km 40 sec/km

HOPE IT HELPS