distance between parallel lines 4x+3y+12=0 and 4x+3y-6=0
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82	-3+92-2(282:28:28
reddyraghavendra539:
this is not right one
yes this is not right answer
then why you posted it
no i did not post my 8 year brother is posted
ok
The given lines are
4x−3y=12 =>4x−3y−12=0
4x−3y=−8 =>4x−3y+8=0
The lines are parallel. The distance between the lines is
r=
4
2
+3
2
∣8−(−12)∣
=>r=
5
20
=>r=4
4x−3y=12 =>4x−3y−12=0
4x−3y=−8 =>4x−3y+8=0
The lines are parallel. The distance between the lines is
r=
4
2
+3
2
∣8−(−12)∣
=>r=
5
20
=>r=4
he is the answer
the answer is 4
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