Question

distance between point (5,-3) and (5,8)​

Answer 1

Answer:

ANSWER:-

Given:

Distance between point (5,-3) & (5,8).

To find:

Find distance.

Solution:

We know that, Formula of distance;

d = \sqrt{(x2 - x1) {}^{2} + (y2 - y1) {}^{2} }d=

(x2−x1)

2

+(y2−y1)

2

Here,

⏺️x1= 5 & x2= 5

⏺️y1= -3 & y2= 8

Therefore,

\begin{gathered}= > d = \sqrt{ {(5 - 5)}^{2} + {(8 - ( - 3))}^{2} } \\ \\ = > d = \sqrt{(0) {}^{2} + (8 + 3) {}^{2} } \\ \\ = > d = \sqrt{0 + {(11)}^{2} } \\ \\ = > d = \sqrt{121} \\ \\ = > d = 11\end{gathered}

=>d=

(5−5)

2

+(8−(−3))

2

=>d=

(0)

2

+(8+3)

2

=>d=

0+(11)

2

=>d=

121

=>d=11

Hence,

Distance is 11.

Hope it helps

Answer 2

ANSWER:

√144+121

√265

=16.27units